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The ionization energy of $\mathrm{Li}^{2+}$ is equal to
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The correct answer is:
9hcR
Ionization energy $=\operatorname{Rch} Z^2$
$Z=3$ for $\mathrm{Li}^{2+}$
$\therefore$ Ionization energy $=(3)^2 R c h$
$=9 R c h$
$Z=3$ for $\mathrm{Li}^{2+}$
$\therefore$ Ionization energy $=(3)^2 R c h$
$=9 R c h$
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