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The ions $\mathrm{S}^{2-}, \mathrm{Cl}^{-}, \mathrm{K}^{+}, \mathrm{Ca}^{2+}$ are isoelectronic. Their ionic radii show
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a significant decrease from $\mathrm{S}^{2-}$ to $\mathrm{Ca}^{2+}$
For isoelectronic species, the ionic radii decrease with increase in nuclear charge.
So, the cation with greater + ve charge i.e. $\mathrm{Ca}^{2+}$ will have smaller radius and the anion with greater - ve charge i.e. $\mathrm{S}^{2-}$ will have a larger radius.
$\because$ The ionic radii show a significant decrease from $\mathrm{S}^{2-}$ to $\mathrm{Ca}^{2+}$.
So, the cation with greater + ve charge i.e. $\mathrm{Ca}^{2+}$ will have smaller radius and the anion with greater - ve charge i.e. $\mathrm{S}^{2-}$ will have a larger radius.
$\because$ The ionic radii show a significant decrease from $\mathrm{S}^{2-}$ to $\mathrm{Ca}^{2+}$.
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