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The IUPAC name of the compound $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHC} \equiv \mathrm{CH}$ is
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The correct answer is:
pent-3-en-1-yne
$\stackrel{5}{\mathrm{C}} \mathrm{H}_{3}-\stackrel{4}{\mathrm{C}} \mathrm{C}=\stackrel{3}{\mathrm{C}} \mathrm{H}-\stackrel{2}{\mathrm{C}}=\stackrel{1}{\mathrm{C}} \mathrm{H}$
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