The I-V graphs for two different electrical appliances $ \mathrm{P} $ and $ \mathrm{Q} $ are shown in diagram . If $ R_{p} $ and $ R_{Q} $ be the resistances of the devices, then

Question

The I-V graphs for two different electrical appliances $ \mathrm{P} $ and $ \mathrm{Q} $ are shown in diagram . If $ R_{p} $ and $ R_{Q} $ be the resistances of the devices, then, $ R_{p}=R_{Q} $, $ R_{p}>R_{Q} $, $ R_{p} < R_{Q} $, $ R_{p}=\frac{R_{Q}}{2} $

MARKS App · Accepted Answer

By Ohm's law, $ V=I R \Rightarrow \frac{I}{V}=\frac{1}{R} $ Thus, the slope of I-V graph is reciprocal of resistance. In the given diagram, Slope of $ Q> $ Slope of $ P $ $$ \begin{array}{l} \Rightarrow \frac{1}{R_{0}}>\frac{1}{R_{p}} \ \Rightarrow R_{p}>R_{o} \end{array} $$

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