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Question: Answered & Verified by Expert
The joint equation of the lines passing through the origin and trisecting the first quadrant is
MathematicsPair of LinesMHT CETMHT CET 2022 (08 Aug Shift 1)
Options:
  • A $\sqrt{3} x^2-4 x y+\sqrt{3} y^2=0$
  • B $x^2-\sqrt{3} x y-y^2=0$
  • C $3 x^2-y^2=0$
  • D $x^2+\sqrt{3} x y-y^2=0$
Solution:
2079 Upvotes Verified Answer
The correct answer is: $\sqrt{3} x^2-4 x y+\sqrt{3} y^2=0$
$\begin{aligned} & y=\tan 30^{\circ} x \text { and } y=\tan 60^{\circ} x \\ & \Rightarrow y=\frac{1}{\sqrt{3}} x \text { and } y=\sqrt{3} \cdot x \\ & \Rightarrow x-\sqrt{3} y=0 \text { and } \sqrt{3} x-y=0\end{aligned}$


Joint equation $(x-\sqrt{3} y)(\sqrt{3} x-y)=0$ $\Rightarrow \sqrt{3} x^2-4 x y+\sqrt{3} y^2=0$

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