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Question: Answered & Verified by Expert
The joint equation of two lines through the origin each making an angle of $30^{\circ}$ with the $\mathrm{Y}$ - axis is
MathematicsPair of LinesMHT CETMHT CET 2020 (20 Oct Shift 1)
Options:
  • A $x^{2}-3 y^{2}=0$
  • B $x^{2}+3 y^{2}=0$
  • C $x^{2}-y^{2}=0$
  • D $\cdot 2 x^{2}-3 y^{2}=0$
Solution:
1295 Upvotes Verified Answer
The correct answer is: $x^{2}-y^{2}=0$


$\therefore$ Slope of lines are $=m_{1}=\tan 60^{\circ}=\sqrt{3}$ and $\mathrm{m}_{2}=\tan 120^{\circ}=\tan \left(90^{\circ}+30^{\circ}\right)=-\sqrt{3}$
Their equations are $y=\sqrt{3} x$ and $y=-\sqrt{3} x$ i.e. $\sqrt{3} x-y=0$ and $\sqrt{3} x+y=0$
Joint equation is $(\sqrt{3} x-y)(\sqrt{3} x+y)=0 \Rightarrow 3 x^{2}-y^{2}=0$

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