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The length of a potentiometer wire is $L$. A cell of e.m.f. $E$ is balanced at a length $\frac{L}{3}$ from the positive end of the wire. If the length of the wire is increased $\frac{L}{2}$ at what distance will the same cell gives a balance point?
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The correct answer is:
$\frac{L}{2}$
Let $x$ be the required balance length.
Potential gradient in the first case $=\frac{E_0}{L}$

From equation (1) and (2), we get
$\begin{aligned} & \frac{E_0}{3}=\left(\frac{2 E_0}{3 L}\right) x \\ & \Rightarrow x=\frac{L}{2}\end{aligned}$
Potential gradient in the first case $=\frac{E_0}{L}$

From equation (1) and (2), we get
$\begin{aligned} & \frac{E_0}{3}=\left(\frac{2 E_0}{3 L}\right) x \\ & \Rightarrow x=\frac{L}{2}\end{aligned}$
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