Search any question & find its solution
Question:
Answered & Verified by Expert
The length of latus rectum of the parabola whose focus is at $(1,-2)$ and directrix is
the line $x+y+3=0$ is
Options:
the line $x+y+3=0$ is
Solution:
1599 Upvotes
Verified Answer
The correct answer is:
$2 \sqrt{2}$ units
$\hat{f}^{(1,-2)}$
$x+y+3=0$
Distance of focus from
$\text { Dizectrix }=22$
$\begin{array}{l}
1^{2} \text { distance } \\
=\frac{|1-2+3|}{\sqrt{2}} \\
=\sqrt{2} .
\end{array}$
Length of L.R
$=2 \sqrt{2}$
$x+y+3=0$
Distance of focus from
$\text { Dizectrix }=22$
$\begin{array}{l}
1^{2} \text { distance } \\
=\frac{|1-2+3|}{\sqrt{2}} \\
=\sqrt{2} .
\end{array}$
Length of L.R
$=2 \sqrt{2}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.