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The length of the diameter of the circle \(x^2+y^2-6 x-8 y=0\) is units
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10
Cirle is \(x^2+y^2-6 x-8 y=0\)
Radius of circle is,
\(r=\sqrt{g^2+f^2-c}=\sqrt{3^2+4^2-0}=5 \text { units }\)
Diameter \(=2 r=10\) units
Radius of circle is,
\(r=\sqrt{g^2+f^2-c}=\sqrt{3^2+4^2-0}=5 \text { units }\)
Diameter \(=2 r=10\) units
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