The length of the shadow of a pole inclined at $ 10^{\circ} $ to the vertical towards the sun is $ 2.05 $ metres, when the elevation of the sun is $ 38^{\circ} $. The length of the pole is

Question

The length of the shadow of a pole inclined at $ 10^{\circ} $ to the vertical towards the sun is $ 2.05 $ metres, when the elevation of the sun is $ 38^{\circ} $. The length of the pole is, $ \frac{2.05 \sin 38^{\circ}}{\sin 42^{\circ}} $, $ \frac{2.05 \sin 42^{\circ}}{\sin 38^{\circ}} $, $ \frac{2.05 \cos 38^{\circ}}{\cos 42^{\circ}} $, None of these

MARKS App · Accepted Answer

sin 38 ° l = sin S P O 2.05 = sin 180 ° - 38 ° - 90 ° - 10 ° 2.05 ⇒ l = 2.05 sin 38 ° sin 42 ° .

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