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Question: Answered & Verified by Expert
The lengths of major and minor axis of an ellipse are 10 and 8 respectively and its major axis along the $y$-axis. The equation of the ellipse referred to its center as origin is
MathematicsEllipseJEE Main
Options:
  • A $\frac{x^2}{25}+\frac{y^2}{16}=1$
  • B $\frac{x^2}{16}+\frac{y^2}{25}=1$
  • C $\frac{x^2}{100}+\frac{y^2}{64}=1$
  • D $\frac{x^2}{64}+\frac{y^2}{100}=1$
Solution:
2822 Upvotes Verified Answer
The correct answer is: $\frac{x^2}{16}+\frac{y^2}{25}=1$
Here given that $2 b=10,2 a=8 \Rightarrow b=5, a=4$. Hence the required equation is $\frac{x^2}{16}+\frac{y^2}{25}=1$.

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