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The lengths of the intercepts on the co-ordinate axes made by the plane $5 x+2 y+z-13=0$ are
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Verified Answer
The correct answer is:
$\frac{13}{5}, \frac{13}{2}, 13$ unit
$5 x+2 y+z-13=0$
Putting $y=0 \& z=0$
$\mathrm{x}=\frac{13}{5}$
Putting $z=0 \& x=0$
$y=\frac{13}{2}$
Putting $x=0 \& y=0$
$z=13$
Putting $y=0 \& z=0$
$\mathrm{x}=\frac{13}{5}$
Putting $z=0 \& x=0$
$y=\frac{13}{2}$
Putting $x=0 \& y=0$
$z=13$
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