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The line $3 \mathrm{x}+4 \mathrm{y}-24=0$ intersects the $\mathrm{x}$ -axis at $\mathrm{A}$ and $\mathrm{y}$ -axis at $\mathrm{B}$. Then the circumcentre of the triangle $\mathrm{OAB}$ where $\mathrm{O}$ is the origin is
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The correct answer is:
$(4,3)$
Since circumcentre of right angled triangle lies on the midpoint of hypotenuse.
So mid point of $\mathrm{AB}$ is $\left(\frac{0+8}{2}, \frac{6+0}{2}\right)$ or $(4,3)$
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