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The line $3 x-4 y=5$ is a tangent to the hyperbola $x^2-4 y^2=5$. The point of contact is
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The correct answer is:
$(3,1)$
Suppose point of contact be $(h, k)$, then tangent is $h x-4 k y-5=0 \equiv 3 x-4 y-5=0$ or $h=3, k=1$
Hence the point of contact is $(3,1)$
Hence the point of contact is $(3,1)$
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