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The line passes through $(1,0)$ and $(-2, \sqrt{3})$ makes an angle of ..... with $x$-axis
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The correct answer is:
$150^{\circ}$
Gradient of the line which passes through $(1,0)$ and $(-2, \sqrt{3})$ is $m=\frac{\sqrt{3}-0}{-2-1}=-\frac{1}{\sqrt{3}}$
$\Rightarrow=\tan ^{-1}\left(-\frac{1}{\sqrt{3}}\right)=150^{\circ}$
$\Rightarrow=\tan ^{-1}\left(-\frac{1}{\sqrt{3}}\right)=150^{\circ}$
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