Search any question & find its solution
Question:
Answered & Verified by Expert
The line $y=\sqrt{3}$ meets the graph $y=\tan x$, where
$x \in\left(0, \frac{\pi}{2}\right)$, in k points. What is k equal to?
Options:
$x \in\left(0, \frac{\pi}{2}\right)$, in k points. What is k equal to?
Solution:
1080 Upvotes
Verified Answer
The correct answer is:
One
Line $\mathrm{y}=\sqrt{3}$ and graph $\mathrm{y}=\tan \mathrm{x}$
Now, we have $\sqrt{3}=\tan \mathrm{x}$
$\Rightarrow \tan x=\tan 60^{\circ}$
$\Rightarrow x=60^{\circ} \quad\left[\because x \in\left(0, \frac{\pi}{2}\right)\right]$
Hence, one intersecting point is possible in the given domain i.e., $\mathrm{k}=1$.
Now, we have $\sqrt{3}=\tan \mathrm{x}$
$\Rightarrow \tan x=\tan 60^{\circ}$
$\Rightarrow x=60^{\circ} \quad\left[\because x \in\left(0, \frac{\pi}{2}\right)\right]$
Hence, one intersecting point is possible in the given domain i.e., $\mathrm{k}=1$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.