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The line $y=6 x+1$ touches the parabola $y^2=24 x$. The coordinates of a point $P$ on this line, from which the tangent to $y^2=24 x$ is perpendicular to the line $y=6 x+1$, is
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The correct answer is:
$(-6,-35)$
Given, equation of line is y = 6x + 1 and
equation of pa rab ola is $y^2=24 x$.
The locus of the point of intersection of
perpendicular tangent to a parabola is its directrix.
So, required point is the point of intersection of
y = 6x + 1 and direc trix x = − 6.
Hence, its coordinates are (− 6, − 35).
equation of pa rab ola is $y^2=24 x$.
The locus of the point of intersection of
perpendicular tangent to a parabola is its directrix.
So, required point is the point of intersection of
y = 6x + 1 and direc trix x = − 6.
Hence, its coordinates are (− 6, − 35).
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