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Question: Answered & Verified by Expert
The line $y=m x+c$ touches the curve $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$, if
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Options:
  • A $c^2=a^2 m^2+b^2$
  • B $c^2=a^2 m^2-b^2$
  • C $c^2=b^2 m^2-a^2$
  • D $a^2=b^2 m^2+c^2$
Solution:
1977 Upvotes Verified Answer
The correct answer is: $c^2=a^2 m^2-b^2$
$y=m x+c$ touches the curve $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$, if $c^2=a^2 m^2-b^2$.

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