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Question: Answered & Verified by Expert
The locus of a point Pα,β moving under the condition that the line y=αx+β is a tangent to the hyperbola x21-y2b2=1 is a conic, with eccentricity equal to
MathematicsHyperbolaJEE Main
Options:
  • A 1
  • B 2
  • C 12
  • D 2
Solution:
1907 Upvotes Verified Answer
The correct answer is: 2
The tangent to the hyperbola x21-y2b2=1 is y=mx±m2-b2
Given that, y=αx+β is a tangent to the hyperbola.
So, m=α and m2-b2=β2
α2-b2=β2
The locus is x2-y2=b2, which is a hyperbola having eccentricity =2

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