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The logic gate represented in following figure is

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Verified Answer
The correct answer is:
OR Gate

$$
\text { Truth Table of this gate }
$$

$$
\begin{aligned}
& Y^{\prime}=\overline{A+B}=\bar{A} \cdot \bar{B} \\
& \text { and } Y=\overline{Y^{\prime}}=\overline{\bar{A}} \cdot \overline{\bar{B}}=\bar{A}+\overline{\bar{B}}=A+B
\end{aligned}
$$
This is the boolean expression for the OR gate.
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