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Question: Answered & Verified by Expert

The machine as shown has 2 rods of length 1 m connected by a pivot at the top. The end of one rod is connected to the floor by a stationary pivot and the end of the other rod has roller that rolls along the floor in a slot. As the roller goes back and forth, a 2 kg weight moves up and down. If the roller is moving towards right at a constant speed, the weight moves up with a :

PhysicsLaws of MotionJEE MainJEE Main 2017 (09 Apr Online)
Options:
  • A Speed which is 34th of that of the roller when the weight is 0.4 m above the ground
  • B Constant speed
  • C Decreasing speed
  • D Increasing speed
Solution:
1434 Upvotes Verified Answer
The correct answer is: Decreasing speed



vA=dxdt=d2lcosθdt=-2lsinθdθdt and 

Vertical velocity of BvB=dydt=dlsinθdt=lcosθdθdt

vAvB=-2tanθvB=-vAcotθ2 
 
θincrease

cotθdecrease

Hence, vBdecrease.

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