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The magnetic field at a perpendicular distance of one metre from a wire carrying current of $1 \mathrm{~A}$ is
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Verified Answer
The correct answer is:
$2 \times 10^{-7} \mathrm{~T}$
Magnetic field due to wire is given by,
$$
\begin{aligned}
& B=\frac{\mu_0 i}{2 \pi r} \\
& B=\frac{4 \pi \times 10^{-7} \times 1}{2 \pi \times 1}=2 \times 10^{-7} T
\end{aligned}
$$
$$
\begin{aligned}
& B=\frac{\mu_0 i}{2 \pi r} \\
& B=\frac{4 \pi \times 10^{-7} \times 1}{2 \pi \times 1}=2 \times 10^{-7} T
\end{aligned}
$$
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