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The magnetic field at point $P$ of given figure due to carrying of current $I$ by a conductor of radius $R$, is
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Verified Answer
The correct answer is:
$\frac{\mu_0 l}{2 \pi r} \mathrm{~T}$
Magnetic field due to a current carrying
conductor at an outside point is given by
$B=\frac{\mu_0 I}{2 \pi r} \mathrm{~T}$
conductor at an outside point is given by
$B=\frac{\mu_0 I}{2 \pi r} \mathrm{~T}$
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