The magnetic field at the center of current carrying circular loop is B 1 . The magnetic field at a distance of 3 times radius of the given circular loop from the center on its axis is B 2 . The value of B 1 B 2 will be

Question

The magnetic field at the center of current carrying circular loop is B 1 . The magnetic field at a distance of 3 times radius of the given circular loop from the center on its axis is B 2 . The value of B 1 B 2 will be, 9 : 4, 12 : 5, 8 : 1, 5 : 3

MARKS App · Accepted Answer

Magnetic field at the centre of the loop i.e. B 1 = μ 0 i 2 R Magnetic field on the axis of the loop is, B 2 = μ 0 i R 2 2 R 2 + x 2 3 2 = μ 0 i × R 2 2 R 2 + 3 R 2 3 2 = μ 0 i × R 2 2 × 8 R 3 = μ 0 i 2 × 8 R Therefore, the ratio B 1 B 2 = 8 1

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