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Question: Answered & Verified by Expert
The magnetic field of a plane electromagnetic wave is given by B=B0i^coskz-ωt+B1j^coskz+ωt, where B0=3×105 T and B1=2×106 T. The RMS value of the force experienced by a stationary charge Q=104 C at z=0 is closest to
PhysicsElectromagnetic WavesJEE Main
Options:
  • A 0.1 N
  • B 0.9 N
  • C 3×102 N
  • D 0.6 N
Solution:
1213 Upvotes Verified Answer
The correct answer is: 0.6 N
B=B0i^coskz-ωt+B1j^coskz+ωt
B0=3×10-5 T     B1=2×10-6T
Electric filed associated with it is,
E=-B0cj^coskz-ωt-B1ci^coskz+ωt
Here, c is speed of light in vacuum.
At z=0,
Frms=QB0c2+QB1c22
Here c is speed of light in vacuum.
=10-4×3×10-5×3×1082+10-4×2×10-6×3×10822
=0.81+0.00362=0.6N

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