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Question: Answered & Verified by Expert
The magnetic field of an electromagnetic wave is given by:
B=1.6×10-6cos 2×107z+6×1015t 2i^+j^Wbm2 
The associated electric field will be:
PhysicsElectromagnetic WavesJEE MainJEE Main 2019 (08 Apr Shift 2)
Options:
  • A E=4.8×102 cos 2×107z-6×1015t -2 j^+i^Vm 
  • B E=4.8×102 cos 2×107z+6×1015t i^-2 j^Vm
  • C E=4.8×102 cos 2×107z+6×1015t -i^+2j^Vm
  • D E=4.8×102 cos 2×107z-6×1015t 2i^+ j^Vm
Solution:
2833 Upvotes Verified Answer
The correct answer is: E=4.8×102 cos 2×107z+6×1015t -i^+2j^Vm
Given magnetic field, B=1.6×10-6cos2×107z+6×1015t2i^+j^Wbm2
The relation between magnetic field and electric field is E=cB=(3×108)×(1.6×10-6×5)=4.8×102×5
The direction of light propagation will be along E×B .
E=4.8×102cos2×107z+6×1015t-i^+2j^Vm

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