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Question: Answered & Verified by Expert
The magnetic flux linked with a coil at any instant ' $t$ ' is given by $\varphi=$ $5 t^3-100 t+300$, the e.m.f. induced in the coil at $t=2$ second is
PhysicsElectromagnetic InductionJEE Main
Options:
  • A $-40 \mathrm{~V}$
  • B $40 \mathrm{~V}$
  • C $140 \mathrm{~V}$
  • D $300 \mathrm{~V}$
Solution:
2070 Upvotes Verified Answer
The correct answer is: $40 \mathrm{~V}$
$e=-\frac{d \phi}{d t}=-\frac{d}{d t}\left(5 t^3-100 t+300\right)$
$=-\left(15 t^2-100\right)$ at $t=2 \mathrm{sec} ; e=40 \mathrm{~V}$

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