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The magnitude of $I$ in ampere unit is
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1560 Upvotes
Verified Answer
The correct answer is:
$0.1$
Consider the diagram with current distribution as shown below.
As voltage is same in parallel combination, so
$\begin{aligned}
&60 I=(15+5) I_{1} \\
&60 I=20 I_{1} \text { or } I_{1}=3 I...(i)
\end{aligned}$
Similarly, $(15+5) I_{1}=10\left(1-I-I_{1}\right)$
$\Rightarrow \quad 2 I_{1}=1-I-I_{1}$
$\Rightarrow \quad 3 I_{1}=1-I$
$\Rightarrow \quad 3(3 I)=1-I$ [Using Eq. (i)]
$10 I=1$
or $\quad I=\frac{1}{10}=0.1 \mathrm{~A}$
As voltage is same in parallel combination, so
$\begin{aligned}
&60 I=(15+5) I_{1} \\
&60 I=20 I_{1} \text { or } I_{1}=3 I...(i)
\end{aligned}$
Similarly, $(15+5) I_{1}=10\left(1-I-I_{1}\right)$
$\Rightarrow \quad 2 I_{1}=1-I-I_{1}$
$\Rightarrow \quad 3 I_{1}=1-I$
$\Rightarrow \quad 3(3 I)=1-I$ [Using Eq. (i)]
$10 I=1$
or $\quad I=\frac{1}{10}=0.1 \mathrm{~A}$
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