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The magnitude of magnetic fields at a distacne 'r' from the centre of a short bar magnet, in longitudinal position to transverse position is in the ratio
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2:1
For longitudenal positions magnetic field will be $B_{1} \alpha \frac{2 M}{d^{3}}$
For transverse positions magnetic field will be $B_{2} \alpha \frac{M}{d^{3}}$
$\therefore \frac{B_{1}}{B_{2}}=2: 1$
For transverse positions magnetic field will be $B_{2} \alpha \frac{M}{d^{3}}$
$\therefore \frac{B_{1}}{B_{2}}=2: 1$
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