The magnitude of the maximum acceleration is π times that of the maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is

Question

The magnitude of the maximum acceleration is π times that of the maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is, 4, 2, 1, 0.5

MARKS App · Accepted Answer

Maximum acceleration = Maximum velocity × π i.e., ω 2 A = π ω A where A is amplitude and ω is angular velocity. ⇒ ω = π ⇒ 2 π T = π ⇒ T = 2 s

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