$2$ -bromopentane gives $2$ -pentene as the major product according to Saytzeff's rule as it is more substituted alkene

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CHBr}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3\stackrel{\mathrm{alc}.\mathrm{KOH}}{\to }{\mathrm{CH}}_2=\mathrm{CH}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3 \\ (\mathrm{Hofmann} \mathrm{product}, \mathrm{least} \mathrm{substituted} \mathrm{alkene}) \end{gathered}$$

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CHBr}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3\stackrel{\mathrm{alc}.\mathrm{KOH}}{\to }{\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_2-{\mathrm{CH}}_3 \\ (\mathrm{Satzeff}\text{'}\mathrm{s} \mathrm{product}, \mathrm{more} \mathrm{substituted} \mathrm{alkene}) \end{gathered}$$