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Question: Answered & Verified by Expert
The major product in the following reaction at $25^{\circ} \mathrm{C}$ is -
ChemistryCarboxylic Acid DerivativesKVPYKVPY 2012 (SA)
Options:
  • A $\mathrm{CH}_{3} \mathrm{CONHCH}_{2} \mathrm{CH}_{3}$
  • B $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{NCH}_{2} \mathrm{CH}_{3}$
  • C $\mathrm{NH}_{3}{ }^{+} \mathrm{CH}_{2} \mathrm{CH}_{3} \cdot \mathrm{CH}_{3} \mathrm{COO}^{-}$
  • D $\mathrm{CH}_{3} \mathrm{CON}=\mathrm{CHCH}_{3}$
Solution:
2809 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_{3} \mathrm{CONHCH}_{2} \mathrm{CH}_{3}$
$\mathrm{H}_{3} \mathrm{C}-\mathrm{COOH} \stackrel{\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}}{\longrightarrow} \mathrm{H}_{3} \mathrm{C}-\mathrm{COO}^{-} \cdot \mathrm{NH}_{3}-\mathrm{CH}_{2} \mathrm{CH}_{3} \rightarrow \mathrm{H}_{3} \mathrm{C}-\mathrm{CO}-\mathrm{NH}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$

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