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The major product in the following reaction is

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In the given reaction, the final product is as follows :

Here, $-\mathrm{CH}_3$ will make bond with $-\mathrm{COO}$ of ring. Hence, we get the product as shown.

Here, $-\mathrm{CH}_3$ will make bond with $-\mathrm{COO}$ of ring. Hence, we get the product as shown.
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