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The major product obtained in the following reaction is:

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LiAlH $_{4}$ is a nucleophilic reducing agent, hence it will reduce $-\mathrm{COOH}$ to $\mathrm{CH}_{2} \mathrm{OH},-\mathrm{CO}$ to $-\mathrm{CHOH}$ and $-\mathrm{NO}_{2}$ to
$\mathrm{NH}_{2}$ but does not reduce $\mathrm{C}=\mathrm{C}$ linkage.
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