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The major product obtained when ethanol is heated with excess of conc. $\mathrm{H}_2 \mathrm{SO}_4$ at $443 \mathrm{~K}$ is
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The correct answer is:
ethene
The major product obtained when ethanol is heated with excess of conc. $\mathrm{H}_2 \mathrm{SO}_4$ at $443 \mathrm{~K}$ is ethene. The reaction involve is as follows
$$
\underset{\text { Ethanol }}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}} \stackrel{\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4}{443 \mathrm{~K}} \underset{\text { Ethenc }}{\mathrm{CH}_2}=\mathrm{CH}_2+\mathrm{H}_2 \mathrm{O}
$$
$$
\underset{\text { Ethanol }}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}} \stackrel{\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4}{443 \mathrm{~K}} \underset{\text { Ethenc }}{\mathrm{CH}_2}=\mathrm{CH}_2+\mathrm{H}_2 \mathrm{O}
$$
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