The mass and the diameter of a planet are three times of the respective values for the earth. If the time period of oscillation of a simple pendulum on earth is 2 s , then the time period of oscillation of the same pendulum on the surface of the given planet would be

Question

The mass and the diameter of a planet are three times of the respective values for the earth. If the time period of oscillation of a simple pendulum on earth is 2 s , then the time period of oscillation of the same pendulum on the surface of the given planet would be, 3 2 s, 2 3 s, 3 2 s, 2 3 s

MARKS App · Accepted Answer

We know that, g = G M R 2 ⇒ g p g e = M p M e × R e R p 2 = 3 × 1 9 = 1 3 Also, T = 2 π 1 g ⇒ T p T e = g e g p = 3 ⇒ T p = 3 T e Time period at earth for seconds pendulum = 2 s ∴ T p = 2 3 s

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