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The mass of glucose to be dissolved in $50 \mathrm{~g}$ of water to get $0.3$ molal solution is
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$2.7 \mathrm{~g}$
Molecular mass of glucose $=180 \mathrm{~g} / \mathrm{mol}$
Mass of water $=50 \mathrm{~g}=0.05 \mathrm{~kg}$
Molality $(m)=\frac{\text { Mass }}{\text { Molar mass } \times \text { mass of solvent }(\text { in kg) }}$
$0.3=\frac{\text { Mass }}{160 \times 0.05}$
Mass $=2.7 \mathrm{~g}$
Mass of water $=50 \mathrm{~g}=0.05 \mathrm{~kg}$
Molality $(m)=\frac{\text { Mass }}{\text { Molar mass } \times \text { mass of solvent }(\text { in kg) }}$
$0.3=\frac{\text { Mass }}{160 \times 0.05}$
Mass $=2.7 \mathrm{~g}$
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