The mass of Haemoglobin in mg required to protect from coagulation of 50 mL of a gold sol on adding 5 mL of 10 % NaCl solution is: (gold number of Haemoglobin = 0 . 03 )

Question

The mass of Haemoglobin in mg required to protect from coagulation of 50 mL of a gold sol on adding 5 mL of 10 % NaCl solution is: (gold number of Haemoglobin = 0 . 03 ), 0 . 03, 0 . 75, 0 . 30, 0 . 15

MARKS App · Accepted Answer

Gold number is the number of milligram of the protective colloid which prevent the coagulation of 10 ml of gold sol when 1 ml of a 10 % solution of sodium chloride is added to it. Here, gold number of Hb = 0 . 03 . So, weight of Hb require for 5 ml of gold is 0 . 03 mg . So, weight require for 50 ml of gold solution = 0 . 15 .

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