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The masses of neutron, proton and deutron in amu are 1.00893, 1.00813 and 2.01473, respectively. The packing fraction of the deutron in amu is
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The correct answer is:
$11.65 \times 10^{-4}$
$m_n=1.00893, m_p=1.00813, m_d=201473$
Deuteron $\left.{ }_1 \mathrm{H}^2\right)$ nucleus consist of one proton and one neutron.
$\begin{aligned}
\therefore \text {Mass defect } & \Delta m=\left(m_n+m_p\right)-m_d \\
& =(1.00893+1.00813)-201473 \\
& =0.00233
\end{aligned}$
$\begin{aligned} \text {Packing fraction } & =\frac{\Delta m}{A} \\ & =\frac{0.00233}{2}=11.65 \times 10^{-4}\end{aligned}$
Deuteron $\left.{ }_1 \mathrm{H}^2\right)$ nucleus consist of one proton and one neutron.
$\begin{aligned}
\therefore \text {Mass defect } & \Delta m=\left(m_n+m_p\right)-m_d \\
& =(1.00893+1.00813)-201473 \\
& =0.00233
\end{aligned}$
$\begin{aligned} \text {Packing fraction } & =\frac{\Delta m}{A} \\ & =\frac{0.00233}{2}=11.65 \times 10^{-4}\end{aligned}$
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