The maximum and minimum tension in the string whirling in a vertical circle of the radius 2 . 5 m with constant speed are in the ratio 5 : 3 then its velocity is ( g = 9.8 m s - 2 )

Question

The maximum and minimum tension in the string whirling in a vertical circle of the radius 2 . 5 m with constant speed are in the ratio 5 : 3 then its velocity is ( g = 9.8 m s - 2 ), 98 m s - 1, 7 m s - 1, 490 m s - 1, 4.9 m s - 1

MARKS App · Accepted Answer

In this problem it is assumed that particle although moving in a vertical loop but it speed remain constant Tension at lowest point T m a x = m v 2 r + m g Tension at highest point T m i n = m v 2 r - m g T m a x T m i n = m v 2 r + m g m v 2 r - m g = 5 3 3 m v 2 r + 3 m g = 5 m v 2 r - 5 m g 2 m v 2 r = 8 m g v = 4 r g = 4 × 2.5 × 9.8 = 98 m s - 1

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