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The maximum distance between the transmitting and receiving TV towers is $65 \mathrm{~km}$. If the ratio of the heights of the TV transmitting tower to receiving tower is $36: 49$, the heights of the transmitting and receiving towers respectively are (radius of earth $=6400 \mathrm{~km}$)
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The correct answer is:
70.3 m, 95.7 m
From Eqs. (i) and (ii), we get
and
$\begin{aligned}
& h_T=70.3 \mathrm{~m} \\
& h_R=95.7 \mathrm{~m}
\end{aligned}$
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