The maximum kinetic energy of a photoelectron is 3 eV . Its stopping potential is

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Question: Answered & Verified by Expert

The maximum kinetic energy of a photoelectron is

3 eV

. Its stopping potential is

PhysicsDual Nature of MatterNEET

Options:

A $3 V$
B $1 V$
C $6 V$
D $2 V$

Solution:

2007 Upvotes Verified Answer

The correct answer is:

3 V

Here,

K_{\max} = 3 eV

Maximum kinetic energy is given by:

\begin{matrix} K_{\max} = e V_{0} \\ 3 eV = e \times V_{0} \\ 3 V = V_{0} \end{matrix}

∴

Stopping potential

V_{0} = 3 V

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