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The maximum kinetic energy of the emitted photoelectrons in photoelectric effects is independent of:
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The correct answer is:
Intensity of incident radiation
By photoelectric equation
$\begin{aligned} & \mathrm{KE}_{\max }=h f-\phi_0 \\ & \mathrm{KE}_{\max }=\frac{h c}{\lambda}-\frac{h c}{\lambda_0}\end{aligned}$
$\mathrm{KE}_{\max }$ is independent of intensity of incident radiation.
$\begin{aligned} & \mathrm{KE}_{\max }=h f-\phi_0 \\ & \mathrm{KE}_{\max }=\frac{h c}{\lambda}-\frac{h c}{\lambda_0}\end{aligned}$
$\mathrm{KE}_{\max }$ is independent of intensity of incident radiation.
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