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The maximum power drawn out of the cell from a source is given by (where $r$ is internal resistance)
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The correct answer is:
$E^2 / 4 r$
$i=\frac{E}{r+R} \Rightarrow P=i^2 R \Rightarrow P=\frac{E^2 R}{(r+R)^2}$
Power is maximum when $r=R \Rightarrow P_{\text {max }}=E^2 / 4 r$
Power is maximum when $r=R \Rightarrow P_{\text {max }}=E^2 / 4 r$
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