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The maximum value attained by the tension in the string of a swinging pendulum is four times the minimum value it attains. There is no slack in the string. The angular amplitude of the pendulum is
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The correct answer is:
$60^{\circ}$
$\quad T_{\max }-m g=\frac{m v^{2}}{R} \ldots .(i)$
from energy cons.
$\mathrm{ki}+\mathrm{ui}=\mathrm{kf}+u f$ $\mathrm{O}+\mathrm{mg}(\mathrm{R}-\mathrm{R} \cos \theta)=\frac{1}{2} \mathrm{mv}^{2}+0$ $\mathrm{~V}^{2}=2 \mathrm{gR}(1-\cos \theta)$
Put in eq. (i)
$\begin{array}{l}
T_{\max }=3 \mathrm{mg}-2 \mathrm{mg} \cos \theta \\
\frac{\mathrm{T}_{\max }}{\mathrm{T}_{\min }}=4 \\
\theta=60^{\circ} \\
\text { (B) }
\end{array}$
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