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Question: Answered & Verified by Expert
The maximum value of the function f(x)=ex+xlnx on the interval 1x2 is
MathematicsApplication of DerivativesKVPYKVPY 2020 (SB/SX)
Options:
  • A e2+ln2+1
  • B e2+2ln2
  • C eπ/2+π2lnπ2
  • D e3/2+32ln32
Solution:
2036 Upvotes Verified Answer
The correct answer is: e2+2ln2

f'(x)=ex+1+lnx>0



(as x[1,2])



f(x) increases in [1,2]

fmax=f(2)=e2+2n2


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