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Question: Answered & Verified by Expert
The milar enthalpy change for $\mathrm{H}_{2} \mathrm{O}(1) \rightleftharpoons \mathrm{H} 2 \mathrm{O}(\mathrm{g})$ at $373 \mathrm{~K}$ and $1 \mathrm{~atm}$ is $41 \mathrm{~kJ} / \mathrm{mol}$. Assuming ideal behavior, the internal energy change for vaporization of 1 mol of water at $373 \mathrm{~K}$ and 1 atm in $\mathrm{kJ} \mathrm{mil}^{-1}$ is
ChemistryThermodynamics (C)KVPYKVPY 2014 (SB/SX)
Options:
  • A $30.2$
  • B $41.0$
  • C $48.1$
  • D $37.9$
Solution:
2404 Upvotes Verified Answer
The correct answer is: $37.9$
$\quad \Delta \mathrm{E}=\Delta \mathrm{H}-\Delta(\mathrm{PV})=\Delta \mathrm{H}-\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}$

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