The minimum pressure required to compress 600 dm 3 of a gas at 1 bar to 150 dm 3 at 40 ° C is

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Question: Answered & Verified by Expert

The minimum pressure required to compress

600 {dm}^{3}

of a gas at

1

bar to

150 {dm}^{3}

at

40 ° C

is

ChemistryStates of MatterNEETNEET 2020 (Phase 2)

Options:

A $4.0 bar$
B $0.2 bar$
C $1.0 bar$
D $2.5 bar$

Solution:

1241 Upvotes Verified Answer

The correct answer is:

4.0 bar

By Boyle's law

P_{1} V_{1} = P_{2} V_{2}

1 bar \times 600 {dm}^{3} = P_{2} \times 150 {dm}^{3}

P_{2} = 4

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