The minimum volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution ( K s p of P b C l 2 = 3.2 × 10 - 8 ;atomic mass of P b = 207 u ) is:

Question

The minimum volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution ( K s p of P b C l 2 = 3.2 × 10 - 8 ;atomic mass of P b = 207 u ) is:, 1.798 L, 0.36 L, 17.98 L, 0.18 L

MARKS App · Accepted Answer

( K s p ) P b C l 2 = 32 × 10 - 9 PbCl 2 = Pb 2 + s + 2 Cl - 2 s K s p = P b 2 + 2 C l - 2 K s p = 4 s 3 = 32 × 10 - 9 s 3 = 8 × 10 - 9 s = 2 × 10 - 3 M w M . w × 1 V L = 2 × 10 - 3 0.1 278 × 1 V L = 2 × 10 - 3 V L = 0.1 × 1000 278 × 2 = 0.18 L

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