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The minimum wavelength of X-ray emitted by X-ray tube is $0.4125 Å$. The accelerating voltage is
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Verified Answer
The correct answer is:
30 kV
From the formula
$\begin{aligned} e V & =h \frac{c}{\lambda} \\ V & =\frac{h c}{e \lambda}=\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{1.6 \times 10^{-19} \times 0.4125 \times 10^{-10}} \\ & =30 \times 10^3 \text { volt }=30 \mathrm{kvolt}\end{aligned}$
$\begin{aligned} e V & =h \frac{c}{\lambda} \\ V & =\frac{h c}{e \lambda}=\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{1.6 \times 10^{-19} \times 0.4125 \times 10^{-10}} \\ & =30 \times 10^3 \text { volt }=30 \mathrm{kvolt}\end{aligned}$
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